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成绩明细历史记录：按提交年月日分类，每个分类标记最高分

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新增 DataService::dayKeyOf()，日期键一律用服务端本地时区计算（避免 UTC 导致东八区零点前后错一天）；aggregateByStudent 为 attempts_list 每项附加 day/day_best/day_count，expandAttempts 透传。

弹窗按天分组渲染分组行（日期 + 共N次 + 最高X分），组内新到旧；当日最高标签仅在当天有多次提交时显示，避免单次日每行都挂标签。

修复：submit_ts=0（时间未知）的记录原本被误标为第1次（升序排序 idx=1 但展示在末尾），现显示 -；未知时间统一归入「未知时间」组。

aggregate 单测 17 -> 33（跨天归属/日内次数/每日最高/未知时间组/时区边界 00:30 与 23:30）；全量 148 项全绿。
This commit is contained in:
nxxy335
2026-09-14 07:28:02 +08:00
parent eb5d06d392
commit 555f500dc7
4 changed files with 186 additions and 31 deletions
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tests/test-aggregate.php
+69
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@@ -89,6 +89,75 @@ $r4 = $agg4['rows'][0];
check('单次提交 attempts = 1', ($r4['attempts'] ?? 0) === 1);
check('单次提交 attempts_list = 1', count($r4['attempts_list'] ?? []) === 1);
echo "\n== 按提交时间年月日分组：每个分类内标记当日最高 ==\n";
/** 按 [时间戳, 分数] 造行；ts=0 表示时间未知 */
function makeRowsAt(string $sid, array $items): array
{
$rows = [];
foreach ($items as $it) {
[$ts, $sc] = $it;
$rows[] = [
'sid' => $sid,
'name' => '测试生',
'cls' => '1班',
'grp' => 'A',
'score' => $sc,
'submit_ts' => $ts,
'submit_at' => $ts > 0 ? date('Y-m-d H:i:s', $ts) : '-',
'duration' => 120,
'duration_txt' => '2分0秒',
'answer_id' => 'ans-' . $ts,
'matched' => true,
'temp_save' => false,
];
}
return $rows;
}
// 09-08 三次（70/95/88），09-09 两次（60/90）
$rows5 = makeRowsAt('S005', [
[strtotime('2026-09-08 09:00:00'), 70.0],
[strtotime('2026-09-08 11:00:00'), 95.0],
[strtotime('2026-09-08 15:00:00'), 88.0],
[strtotime('2026-09-09 10:00:00'), 60.0],
[strtotime('2026-09-09 14:00:00'), 90.0],
]);
$agg5 = DataService::aggregateByStudent($rows5, true);
$r5 = $agg5['rows'][0];
$al5 = $r5['attempts_list'];
check('5 次提交 attempts_list = 5', count($al5) === 5);
check('前 3 条归属 2026-09-08', ($al5[0]['day'] ?? '') === '2026-09-08' && ($al5[2]['day'] ?? '') === '2026-09-08',
'got ' . ($al5[0]['day'] ?? '?'));
check('后 2 条归属 2026-09-09', ($al5[3]['day'] ?? '') === '2026-09-09' && ($al5[4]['day'] ?? '') === '2026-09-09',
'got ' . ($al5[3]['day'] ?? '?'));
check('09-08 当天次数 = 3', ($al5[0]['day_count'] ?? 0) === 3, 'got ' . ($al5[0]['day_count'] ?? '?'));
check('09-09 当天次数 = 2', ($al5[3]['day_count'] ?? 0) === 2, 'got ' . ($al5[3]['day_count'] ?? '?'));
$dayBestIdx = array_values(array_filter($al5, fn($a) => !empty($a['day_best'])));
check('每个分类各标记 1 个当日最高（共 2 个）', count($dayBestIdx) === 2, 'got ' . count($dayBestIdx));
check('09-08 当日最高 = 95（第 2 次）', (int)($dayBestIdx[0]['idx'] ?? 0) === 2 && (float)($dayBestIdx[0]['score'] ?? -1) === 95.0,
'got idx=' . ($dayBestIdx[0]['idx'] ?? '?') . ' score=' . ($dayBestIdx[0]['score'] ?? '?'));
check('09-09 当日最高 = 90（第 5 次）', (int)($dayBestIdx[1]['idx'] ?? 0) === 5 && (float)($dayBestIdx[1]['score'] ?? -1) === 90.0,
'got idx=' . ($dayBestIdx[1]['idx'] ?? '?') . ' score=' . ($dayBestIdx[1]['score'] ?? '?'));
check('全局最佳仍是 95（第 2 次）', (int)($al5[1]['is_best'] ?? 0) === 1 || !empty($al5[1]['is_best']));
echo "\n== 时间未知（submit_ts=0）归入「未知时间」分组 ==\n";
$rows6 = makeRowsAt('S006', [[0, 50.0], [0, 80.0]]);
$agg6 = DataService::aggregateByStudent($rows6, true);
$al6 = $agg6['rows'][0]['attempts_list'];
check('时间未知时 day = 空串', ($al6[0]['day'] ?? 'x') === '' && ($al6[1]['day'] ?? 'x') === '',
'got ' . var_export($al6[0]['day'] ?? null, true));
check('未知时间组次数 = 2', ($al6[0]['day_count'] ?? 0) === 2, 'got ' . ($al6[0]['day_count'] ?? '?'));
check('未知时间组内仍标记最高（80）', !empty($al6[1]['day_best']) && (float)($al6[1]['score'] ?? -1) === 80.0);
echo "\n== 日期键时区边界（不能用 UTC，否则零点前后错一天）==\n";
check('00:30 仍算当天（东八区不会退到前一天）',
DataService::dayKeyOf((int)strtotime('2026-09-08 00:30:00')) === '2026-09-08',
'got ' . DataService::dayKeyOf((int)strtotime('2026-09-08 00:30:00')));
check('23:30 仍算当天',
DataService::dayKeyOf((int)strtotime('2026-09-08 23:30:00')) === '2026-09-08',
'got ' . DataService::dayKeyOf((int)strtotime('2026-09-08 23:30:00')));
check('无时间戳时从展示串取日期', DataService::dayKeyOf(0, '2026-09-08 09:41:20') === '2026-09-08');
check('无时间戳且展示串为 - 时返回空串', DataService::dayKeyOf(0, '-') === '');
echo "\n========================================\n";
echo "通过 {$pass} · 失败 {$fail}\n";
exit($fail === 0 ? 0 : 1);