nxxy335
555f500dc7
新增 DataService::dayKeyOf()，日期键一律用服务端本地时区计算（避免 UTC 导致东八区零点前后错一天）；aggregateByStudent 为 attempts_list 每项附加 day/day_best/day_count，expandAttempts 透传。 弹窗按天分组渲染分组行（日期 + 共N次 + 最高X分），组内新到旧；当日最高标签仅在当天有多次提交时显示，避免单次日每行都挂标签。 修复：submit_ts=0（时间未知）的记录原本被误标为第1次（升序排序 idx=1 但展示在末尾），现显示 -；未知时间统一归入「未知时间」组。 aggregate 单测 17 -> 33（跨天归属/日内次数/每日最高/未知时间组/时区边界 00:30 与 23:30）；全量 148 项全绿。
164 lines
8.5 KiB
PHP
164 lines
8.5 KiB
PHP
<?php
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/**
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* 验证 aggregateByStudent 的"考试次数 / 历史明细"修复：
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* 多次提交的学生在 dedupe=true（默认）与 dedupe=false 两种情况下，
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* attempts 都应等于真实提交次数、attempts_list 都应包含全部提交；
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* dedupe 仅影响"代表成绩"那一行取最新或最高分。
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*/
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require __DIR__ . '/../bootstrap.php';
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$fail = 0;
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$pass = 0;
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function check(string $name, bool $cond, string $detail = ''): void
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{
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global $fail, $pass;
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if ($cond) {
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$pass++;
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echo " ✅ {$name}\n";
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} else {
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$fail++;
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echo " ❌ {$name} {$detail}\n";
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}
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}
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/**
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* 构造一个学生的多次提交（模拟 第二周测试 中"陈苏豫 11次"这类数据）
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* 提交时间递增（旧 -> 新），分数有高有低。
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*/
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function makeRows(string $sid, array $scoresByTime): array
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{
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$rows = [];
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$t = 1000; // 递增时间戳
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foreach ($scoresByTime as $sc) {
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$t += 600;
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$rows[] = [
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'sid' => $sid,
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'name' => '测试生',
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'cls' => '1班',
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'grp' => 'A',
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'score' => $sc,
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'submit_ts' => $t,
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'submit_at' => date('Y-m-d H:i:s', $t),
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'duration' => 120,
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'duration_txt'=> '2分0秒',
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'answer_id' => 'ans-' . $t,
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'matched' => true,
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'temp_save' => false,
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];
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}
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return $rows;
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}
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echo "== dedupe=true（默认：代表成绩取最新一份）==\n";
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// 11 次提交：分数各不相同，最新一份是 84.0，最高是 98.0
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$scores = [84.0, 98.0, 96.0, 96.0, 96.0, 94.0, 94.0, 96.0, 90.0, 88.0, 98.0];
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$rows = makeRows('S001', $scores);
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$agg = DataService::aggregateByStudent($rows, true);
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check('聚合后只有 1 行（一人一行）', count($agg['rows']) === 1);
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$r = $agg['rows'][0];
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check('attempts = 11（真实次数，而非被吞成 1）', ($r['attempts'] ?? 0) === 11, 'got ' . var_export($r['attempts'] ?? null, true));
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check('attempts_list 含 11 条（历史可展开全部）', count($r['attempts_list'] ?? []) === 11, 'got ' . count($r['attempts_list'] ?? []));
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check('best_score = 98.0（跨全部尝试的真实最高分）', (float)($r['best_score'] ?? -1) === 98.0, 'got ' . var_export($r['best_score'] ?? null, true));
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// 代表成绩 = 最新一份（数组中最后一个时间 = 98.0，因为 scores 数组最后一个是 98.0；注意最新提交对应最后构造的 98.0）
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check('代表成绩取最新提交 = 98.0', (float)($r['score'] ?? -1) === 98.0, 'got ' . var_export($r['score'] ?? null, true));
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check('attempts_list 项数 idx 连续 1..11', (int)($r['attempts_list'][10]['idx'] ?? 0) === 11);
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check('attempts_list 至少一条 is_best（最高分标记）', count(array_filter($r['attempts_list'], fn($a) => !empty($a['is_best']))) >= 1);
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echo "\n== dedupe=false（代表成绩取最高分）==\n";
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$agg2 = DataService::aggregateByStudent($rows, false);
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$r2 = $agg2['rows'][0];
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check('attempts = 11（与 dedupe 无关，始终真实）', ($r2['attempts'] ?? 0) === 11, 'got ' . var_export($r2['attempts'] ?? null, true));
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check('attempts_list 含 11 条', count($r2['attempts_list'] ?? []) === 11, 'got ' . count($r2['attempts_list'] ?? []));
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check('代表成绩取最高分 = 98.0', (float)($r2['score'] ?? -1) === 98.0, 'got ' . var_export($r2['score'] ?? null, true));
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check('best_score = 98.0', (float)($r2['best_score'] ?? -1) === 98.0, 'got ' . var_export($r2['best_score'] ?? null, true));
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echo "\n== 重考低分也应被统计（历史含低分，且因提交时间更新能被发现）==\n";
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// 先考 90，后重考 70（更低）：考试次数必须=2，最新提交=70
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$rows3 = makeRows('S002', [90.0, 70.0]);
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$agg3 = DataService::aggregateByStudent($rows3, true);
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$r3 = $agg3['rows'][0];
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check('attempts = 2', ($r3['attempts'] ?? 0) === 2, 'got ' . var_export($r3['attempts'] ?? null, true));
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check('attempts_list = 2 条（含低分重考）', count($r3['attempts_list'] ?? []) === 2);
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check('代表成绩取最新 = 70.0', (float)($r3['score'] ?? -1) === 70.0, 'got ' . var_export($r3['score'] ?? null, true));
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check('last_submit_ts 指向最新提交（重考可被高亮发现）', ($r3['last_submit_ts'] ?? 0) === $rows3[1]['submit_ts']);
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echo "\n== 仅 1 次提交不受影响 ==\n";
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$rows4 = makeRows('S003', [85.0]);
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$agg4 = DataService::aggregateByStudent($rows4, true);
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$r4 = $agg4['rows'][0];
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check('单次提交 attempts = 1', ($r4['attempts'] ?? 0) === 1);
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check('单次提交 attempts_list = 1', count($r4['attempts_list'] ?? []) === 1);
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echo "\n== 按提交时间年月日分组：每个分类内标记当日最高 ==\n";
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/** 按 [时间戳, 分数] 造行；ts=0 表示时间未知 */
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function makeRowsAt(string $sid, array $items): array
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{
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$rows = [];
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foreach ($items as $it) {
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[$ts, $sc] = $it;
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$rows[] = [
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'sid' => $sid,
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'name' => '测试生',
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'cls' => '1班',
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'grp' => 'A',
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'score' => $sc,
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'submit_ts' => $ts,
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'submit_at' => $ts > 0 ? date('Y-m-d H:i:s', $ts) : '-',
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'duration' => 120,
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'duration_txt' => '2分0秒',
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'answer_id' => 'ans-' . $ts,
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'matched' => true,
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'temp_save' => false,
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];
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}
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return $rows;
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}
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// 09-08 三次（70/95/88），09-09 两次（60/90）
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$rows5 = makeRowsAt('S005', [
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[strtotime('2026-09-08 09:00:00'), 70.0],
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[strtotime('2026-09-08 11:00:00'), 95.0],
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[strtotime('2026-09-08 15:00:00'), 88.0],
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[strtotime('2026-09-09 10:00:00'), 60.0],
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[strtotime('2026-09-09 14:00:00'), 90.0],
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]);
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$agg5 = DataService::aggregateByStudent($rows5, true);
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$r5 = $agg5['rows'][0];
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$al5 = $r5['attempts_list'];
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check('5 次提交 attempts_list = 5', count($al5) === 5);
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check('前 3 条归属 2026-09-08', ($al5[0]['day'] ?? '') === '2026-09-08' && ($al5[2]['day'] ?? '') === '2026-09-08',
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'got ' . ($al5[0]['day'] ?? '?'));
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check('后 2 条归属 2026-09-09', ($al5[3]['day'] ?? '') === '2026-09-09' && ($al5[4]['day'] ?? '') === '2026-09-09',
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'got ' . ($al5[3]['day'] ?? '?'));
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check('09-08 当天次数 = 3', ($al5[0]['day_count'] ?? 0) === 3, 'got ' . ($al5[0]['day_count'] ?? '?'));
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check('09-09 当天次数 = 2', ($al5[3]['day_count'] ?? 0) === 2, 'got ' . ($al5[3]['day_count'] ?? '?'));
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$dayBestIdx = array_values(array_filter($al5, fn($a) => !empty($a['day_best'])));
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check('每个分类各标记 1 个当日最高（共 2 个）', count($dayBestIdx) === 2, 'got ' . count($dayBestIdx));
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check('09-08 当日最高 = 95（第 2 次）', (int)($dayBestIdx[0]['idx'] ?? 0) === 2 && (float)($dayBestIdx[0]['score'] ?? -1) === 95.0,
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'got idx=' . ($dayBestIdx[0]['idx'] ?? '?') . ' score=' . ($dayBestIdx[0]['score'] ?? '?'));
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check('09-09 当日最高 = 90（第 5 次）', (int)($dayBestIdx[1]['idx'] ?? 0) === 5 && (float)($dayBestIdx[1]['score'] ?? -1) === 90.0,
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'got idx=' . ($dayBestIdx[1]['idx'] ?? '?') . ' score=' . ($dayBestIdx[1]['score'] ?? '?'));
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check('全局最佳仍是 95（第 2 次）', (int)($al5[1]['is_best'] ?? 0) === 1 || !empty($al5[1]['is_best']));
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echo "\n== 时间未知（submit_ts=0）归入「未知时间」分组 ==\n";
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$rows6 = makeRowsAt('S006', [[0, 50.0], [0, 80.0]]);
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$agg6 = DataService::aggregateByStudent($rows6, true);
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$al6 = $agg6['rows'][0]['attempts_list'];
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check('时间未知时 day = 空串', ($al6[0]['day'] ?? 'x') === '' && ($al6[1]['day'] ?? 'x') === '',
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'got ' . var_export($al6[0]['day'] ?? null, true));
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check('未知时间组次数 = 2', ($al6[0]['day_count'] ?? 0) === 2, 'got ' . ($al6[0]['day_count'] ?? '?'));
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check('未知时间组内仍标记最高（80）', !empty($al6[1]['day_best']) && (float)($al6[1]['score'] ?? -1) === 80.0);
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echo "\n== 日期键时区边界（不能用 UTC，否则零点前后错一天）==\n";
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check('00:30 仍算当天（东八区不会退到前一天）',
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DataService::dayKeyOf((int)strtotime('2026-09-08 00:30:00')) === '2026-09-08',
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'got ' . DataService::dayKeyOf((int)strtotime('2026-09-08 00:30:00')));
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check('23:30 仍算当天',
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DataService::dayKeyOf((int)strtotime('2026-09-08 23:30:00')) === '2026-09-08',
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'got ' . DataService::dayKeyOf((int)strtotime('2026-09-08 23:30:00')));
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check('无时间戳时从展示串取日期', DataService::dayKeyOf(0, '2026-09-08 09:41:20') === '2026-09-08');
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check('无时间戳且展示串为 - 时返回空串', DataService::dayKeyOf(0, '-') === '');
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echo "\n========================================\n";
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echo "通过 {$pass} · 失败 {$fail}\n";
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exit($fail === 0 ? 0 : 1);
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